534A - Exam - CodeForces Solution


constructive algorithms implementation math *1100

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Python Code:

import sys
import math

n = int(input())

if n > 1 and n < 4:
    if n == 2: print('1' +  '\n' + '1')
    else:
        print('2' +  '\n' + '1 3')
    sys.exit()

print(n)

i = 2
while i<=n:
    print(i, end = ' ' ); i+=2

i = 1

while i<=n:
    print(i, end = ' '); i+=2

    
        

C++ Code:

#include <iostream>
using namespace std;
int main()
{
	long long n;
	cin>>n;
	if(n<=2)
	{
		cout<<1<<"\n"<<1;
	}
	else if(n==3)
	{
		cout<<2<<"\n"<<1<<" "<<3;
	}
	else if(n%2==0)
	{
		cout<<n<<"\n";
		for(int i=n-1;i>=1;i--)
		{
			cout<<i<<" ";
			i--;
		}
		for(int i=n;i>=2;i--)
		{
			cout<<i<<" ";
			i--;
		}
	}
	else
	{
		cout<<n<<"\n";
		for(int i=n;i>=1;i--)
		{
			cout<<i<<" ";
			i--;
		}
		for(int i=n-1;i>=2;i--)
		{
			cout<<i<<" ";
			i--;
		}
	}
}


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